LaTeX to CAS translator
This mockup demonstrates the concept of TeX to Computer Algebra System (CAS) conversion.
The demo-application converts LaTeX functions which directly translate to CAS counterparts.
Functions without explicit CAS support are available for translation via a DRMF package (under development).
The following LaTeX input ...
{\displaystyle A(z;q) \stackrel{\rm{def}}{=} \frac{1}{1+z} \sum_{n=0}^\infty \frac{(z;q)_n}{(-zq;q)_n}z^n = \sum_{n=0}^\infty (-1)^n z^{2n} q^{n^2}.}
... is translated to the CAS output ...
Semantic latex: A(z;q) \stackrel{\rm{def}}{=} \frac{1}{1+z} \sum_{n=0}^\infty \frac{(z;q)_n}{(-zq;q)_n}z^n = \sum_{n=0}^\infty (-1)^n z^{2n} q^{n^2}
Confidence: 0
Mathematica
Translation:
Information
Symbol info
- (LaTeX -> Mathematica) An unknown or missing element occurred: Empty expression tag. Unable to translate:
Tests
Symbolic
Numeric
SymPy
Translation:
Information
Symbol info
- (LaTeX -> SymPy) An unknown or missing element occurred: Empty expression tag. Unable to translate:
Tests
Symbolic
Numeric
Maple
Translation:
Information
Symbol info
- (LaTeX -> Maple) An unknown or missing element occurred: Empty expression tag. Unable to translate:
Tests
Symbolic
Numeric
Dependency Graph Information
Includes
Is part of
Complete translation information:
{
"id" : "FORMULA_dc8fa1e5b194556af601dae9f85d8fef",
"formula" : "A(z;q) \\stackrel{\\rm{def}}{=} \\frac{1}{1+z} \\sum_{n=0}^\\infty \n\\frac{(z;q)_n}{(-zq;q)_n}z^n = \n\\sum_{n=0}^\\infty (-1)^n z^{2n} q^{n^2}",
"semanticFormula" : "A(z;q) \\stackrel{\\rm{def}}{=} \\frac{1}{1+z} \\sum_{n=0}^\\infty \n\\frac{(z;q)_n}{(-zq;q)_n}z^n = \n\\sum_{n=0}^\\infty (-1)^n z^{2n} q^{n^2}",
"confidence" : 0.0,
"translations" : {
"Mathematica" : {
"translation" : "",
"translationInformation" : {
"tokenTranslations" : {
"Error" : "(LaTeX -> Mathematica) An unknown or missing element occurred: Empty expression tag. Unable to translate: "
}
},
"numericResults" : {
"overallResult" : "SKIPPED",
"numberOfTests" : 0,
"numberOfFailedTests" : 0,
"numberOfSuccessfulTests" : 0,
"numberOfSkippedTests" : 0,
"numberOfErrorTests" : 0,
"wasAborted" : false,
"crashed" : false,
"testCalculationsGroups" : [ ]
},
"symbolicResults" : {
"overallResult" : "SKIPPED",
"numberOfTests" : 0,
"numberOfFailedTests" : 0,
"numberOfSuccessfulTests" : 0,
"numberOfSkippedTests" : 0,
"numberOfErrorTests" : 0,
"crashed" : false,
"testCalculationsGroup" : [ ]
}
},
"SymPy" : {
"translation" : "",
"translationInformation" : {
"tokenTranslations" : {
"Error" : "(LaTeX -> SymPy) An unknown or missing element occurred: Empty expression tag. Unable to translate: "
}
},
"numericResults" : {
"overallResult" : "SKIPPED",
"numberOfTests" : 0,
"numberOfFailedTests" : 0,
"numberOfSuccessfulTests" : 0,
"numberOfSkippedTests" : 0,
"numberOfErrorTests" : 0,
"wasAborted" : false,
"crashed" : false,
"testCalculationsGroups" : [ ]
},
"symbolicResults" : {
"overallResult" : "SKIPPED",
"numberOfTests" : 0,
"numberOfFailedTests" : 0,
"numberOfSuccessfulTests" : 0,
"numberOfSkippedTests" : 0,
"numberOfErrorTests" : 0,
"crashed" : false,
"testCalculationsGroup" : [ ]
}
},
"Maple" : {
"translation" : "",
"translationInformation" : {
"tokenTranslations" : {
"Error" : "(LaTeX -> Maple) An unknown or missing element occurred: Empty expression tag. Unable to translate: "
}
},
"numericResults" : {
"overallResult" : "SKIPPED",
"numberOfTests" : 0,
"numberOfFailedTests" : 0,
"numberOfSuccessfulTests" : 0,
"numberOfSkippedTests" : 0,
"numberOfErrorTests" : 0,
"wasAborted" : false,
"crashed" : false,
"testCalculationsGroups" : [ ]
},
"symbolicResults" : {
"overallResult" : "SKIPPED",
"numberOfTests" : 0,
"numberOfFailedTests" : 0,
"numberOfSuccessfulTests" : 0,
"numberOfSkippedTests" : 0,
"numberOfErrorTests" : 0,
"crashed" : false,
"testCalculationsGroup" : [ ]
}
}
},
"positions" : [ ],
"includes" : [ "z", "x_{n}", "n", "q^{n}", "q", "A(z;q) \\stackrel{\\rm{def}}{=} \\frac{1}{1+z} \\sum_{n=0}^\\infty \\frac{(z;q)_n}{(-zq;q)_n}z^n = \\sum_{n=0}^\\infty (-1)^n z^{2n} q^{n^2}" ],
"isPartOf" : [ "A(z;q) \\stackrel{\\rm{def}}{=} \\frac{1}{1+z} \\sum_{n=0}^\\infty \\frac{(z;q)_n}{(-zq;q)_n}z^n = \\sum_{n=0}^\\infty (-1)^n z^{2n} q^{n^2}" ],
"definiens" : [ ]
}